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Q: Another molarity ( No Answer,   2 Comments )
Subject: Another molarity
Category: Science > Chemistry
Asked by: lilgreeny-ga
List Price: $2.00
Posted: 06 Mar 2006 15:22 PST
Expires: 05 Apr 2006 16:22 PDT
Question ID: 704369
Calculate the volume of a 0.068 M solution of zinc nitrate that would
provide 2.9 g of Zn(NO3)2.

Clarification of Question by lilgreeny-ga on 06 Mar 2006 15:27 PST
I know that you have to do this first Calculate the molar mass of
Zn(NO3)2 to convert from grams to moles, which would be 2.9g x 1
mole/189.41g of Zn(NO3)2...right? ....but I do not know where to go
from there..   Please Help!!!
There is no answer at this time.

Subject: Re: Another molarity
From: gtdamico-ga on 06 Mar 2006 21:25 PST
O.k., here is a logical solution that I came up with:

1st, convert the given mass of Zn(NO3)2 to moles
     2.9g *(1 mole/ 189.4g) = 0.0153 moles Zn(NO3)2

2nd, use this and you are given the concentration should be 0.068M (moles/ L)
     0.0153 moles*(1 L / 0.068 moles) = 0.225L = 225mL


This is logical because if you start off with 0.0153 moles, you need
less than one liter to get the resulting molarity.
Subject: Re: Another molarity
From: latts13-ga on 21 Mar 2006 09:15 PST
Here is my answer:
number of moles= 2.9/189.41=0.0153 mol
Vol= number of moles/ conc= 0.0153/0.068= 0.225 l = 225 ml
Hence, I agree with the other answer given.

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