Cereb
I understand that you just use the circuit to model response of
a simple linerar system.
We will use Lapalce method described here:
RLC Circuits
An Example of the Application of Laplace Transforms
http://people.deas.harvard.edu/~jones/es154/lectures/lecture_0/Laplace/laplace.html%20
Your impedance is :
Z(s) = R2 + Z1(s)
1/Z1(s) = 1/R1 + 1/s*C1
that can be transformed to
Z(s) = R2 + R1*C1*s/( R1 + s*C1) =( R2* (R1 + s*C1) + R1 * C1 *s ) /
( R1 + s * C1)
so that
1/Z(s) = (1 + C1/R1* s) / ( R2 + R2 *C1/R1 *s + C1 *s)
when we do inverse transfrom reduces
First a term reduces to a term proportional toapplied voltage
Second to an exponetial, as shown in example 1;
Now, clickingon link at the bottom of the page
See Symbolic Inverse Laplace Transform Applet
take you to the page which does the inverse and plots the response
In my browser I do not see the [plot] button. Perhaps that step does not work.
You cab use following to plot any simple function:
Plotting applet
http://www.pa.uky.edu/~phy211/graph_applets/plot_graph.html
addtional references:
http://math.fullerton.edu/mathews/c2003/LaplaceTransformBib/Links/LaplaceTransformBib_lnk_1.html
Hedgie 
Request for Answer Clarification by
cerebga
on
14 Mar 2006 21:53 PST
I mistakenly used the comment option when I replied to your answer.
Basically, your answer was not responsive, and I ofered you choices.
Perhaps you elect to respond?

Clarification of Answer by
hedgiega
on
15 Mar 2006 01:11 PST
Cereb
I can understand that you are diappointed if you got 'a flat curve'
I do not understand:
"It is the result I needed, however." Did you mean:
"It is NOT the result I needed, however." amd forgot the 'not'?
In original question you said:
"and ideally also the plot created by a Deadline, Winplot or Zgraph
Program"
I directed you to a webbased plotting applet, which can plot the
exponential curve which is the solution I got for your circuit.
Now it sounds like answer HAS TO use one of these three ploting programs
you mentioned. It also feels like I am talking to a lawyer.
I can help you your problem, but I am not willing to engage in arguments,
for any amount of money.
I do not think it would be expedient to try to introduce the zero star
rating just for this ocassion. It would look good on my resume :)
I will simply withdraw my answer if the dialog will continue this way.
So: There are some problems with the question as posed,
(I am not convinced you really want a diode there which makes the system
nonlinear, and I do not see any inductor in the circuit)
and with understanding the solution,
and with plotting it.
If you are willing and able to accept my expert asistence,
I think those can be overcome by cooperative dialog. I am
willing to give it another try, and as a first step I would
like you to do this:
Go to that plotting applet I suggested and see if you can plot function
x^2 * sin(x)
Describe what you get. This is a test, to see if the applet works
on your machine. You can suggest a different plotting alternative, but
at least you
need to provide a link to such a program 
You cannot assume evryone knows what Zline or whatever plotting ptogram is.
And (if you want to work with me) they have to be multiplaform, like e.g. this one
http://www.duke.edu/~hpgavin/gnuplot.html
I do not have Winplot for Windows 95/98/ME/2K/XP (558K) (27 Feb 2006)
on my machine and do not intend to install MS windows just to use that
particular program.
So, I am expecting your RFC, and please, do not try to enter that 0 star
rating. If you cannot accept my terms for cooperation, just say so. I
will withdraw the answer and write off the time I invested. That is
one risk of the job.
Hedgie

Clarification of Answer by
hedgiega
on
15 Mar 2006 23:53 PST
Cereb
From what you say : "The inverse transform yielded a flat curve"
I gather that you did not understand the answer. I have done the transform
for you, and described result as having two terms. Restating that slightly,
to make it more clear, I said
" when we do the inverse transfrom, we get resulting current having two terms:
First a term is proportional to the applied voltage
Second term is an exponetial, same as the one shown in example 1 "
The formula I gave you relates the value of your components (R1 R2 C1)
to the time constant of the exponentional (the relaxation time of the circuit).
Neither term is a 'flat curve' .
I can clarify and explain the answer furher, but not without cooperation.
As a minimum I would need clarification of the following
I do not understand when you say:
"It is the result I needed, however." Did you mean:
"It is NOT the result I needed, however." amd forgot the 'not'?
So, to sumarize:
" If you do not respond to this request for clarification I
will withdraw the answer. I will write off the time I invested so far."
Hedgie

Request for Answer Clarification by
cerebga
on
16 Mar 2006 11:40 PST
Just as I was to insert my feedback I noticed your addtl. comment. I
will still paste the reply I wrote offline. It offers a clear start
so we can continue.
First I wish to thank you for indicating your willingness to continue.
You posed three questions:
Re: plotting x^2*sin(x)  yes, the 2nd of the three links you listed
gave me that plot
Re: no inductor in the circuit  L1 was used in my sketch. It is at
the extreme left in my sketch
Re: diode  I 'envisioned' the diode as a solution  to preclude a
fluxinduced EMF and charge on C1 to dissipate back through L1. The
desired condition is one where the R1C1 product shall determine the
shape of the voltage decay. Since I am not building the circuit in can
be ignored.
Back to the task at hand  I can see the logic in your solution. I am
satisfied that your answer is correct, even though I cannot follow it
to the point where it demonstrably solves the task that I posted.
I therefore propose that we close this task, with four stars given on
faith, and that I write and post a new and more concise question. You
then have the option to offer an answer of the type I will describe,
or abstain from doing so. This would eliminate further handholding,
provide for an honorable exit and also for a better defined new start.
As to other comments you made:
Re: HAS TO use one of the 3 plotting programs  I said that "if you
know of some applet or online plotting program I could use  by all
means.
Re: missing "NOT"  Both forms effectively mean the same. The
"however" I used was contrasting acknowledged effort with needed
results.
Re: engaging in arguments  I agree with your statement. Arguments
have no place here specifically, and usually not anywhere. I did not
find arguments in my feedback, however.
Re: Zero star  I was following your lead. You introduced
handholding in connection with the offered amount. So I offered to
add to the fee for continuing to completion, or if you decide not to,
that I would accept that and pay the fee and rate the answer as non
responsive. I welcome the choice you made.

Clarification of Answer by
hedgiega
on
16 Mar 2006 19:48 PST
Thank you for your comments and rating. I will look at the new question.
