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Subject:
Probability
Category: Science > Math Asked by: handlit33-ga List Price: $2.00 |
Posted:
03 Apr 2006 15:33 PDT
Expires: 03 May 2006 15:33 PDT Question ID: 715091 |
My brother and I are entered into a lottery of ten people total (including ourselves). Names will be pulled out of a hat, the 1st name through 7th name are the losers. The 8th name pulled is 3rd place winning $20, the 9th name pulled is 2nd place winning $30 and the 10th name pulled is 1st place winning $50. What is the probability that either my brother or me will win 1st, 2nd or 3rd place? I know that if the 1st, 2nd and 3rd names pulled were winners the formula for figuring out the problem would be: 1 - 8/10*7/9*6/8 What is the probability and formula backing the answer for figuring out the original way the question was stated? |
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There is no answer at this time. |
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Subject:
Re: Probability
From: rracecarr-ga on 03 Apr 2006 16:36 PDT |
I know the chance of heads is 1/2 the first time I flip a coin, but what is it the last time? |
Subject:
Re: Probability
From: marcusl-ga on 03 Apr 2006 17:32 PDT |
you have one draw, there are 10 options available, 3 winning options, 7 losing. 3/10 chance you win. also 3/10 your brother wins. combined, you have a 6/10 chance of either of you winning. do your own homework! |
Subject:
Re: Probability
From: rracecarr-ga on 03 Apr 2006 17:44 PDT |
Yes, do your own homework, but don't listen to marcus, or you'll get a bad grade. |
Subject:
Re: Probability
From: handlit33-ga on 03 Apr 2006 19:43 PDT |
This isn't homework, haha. I'm a 26 year old defense contractor, school is a distant memory. I'm just trying to educate myself on a real world situation. |
Subject:
Re: Probability
From: rracecarr-ga on 04 Apr 2006 12:25 PDT |
Ok, well the probability you list in your question is correct for any three randomly drawn names. First three, last three, any three. Essentially, the non-winning picks don't 'count'. You don't even have to look at them. |
Subject:
Re: Probability
From: ansel001-ga on 04 Apr 2006 17:29 PDT |
The probability that either you or you brother or both will win one of the three prizes is: 1 - [Probability you both lose] As Rracecarr mentions, it doesn't matter where in the ten names drawn the three winners lie, the probability is the same. So your formula 1 - 8/10*7/9*6/8 is correct. |
Subject:
Re: Probability
From: berkeleychocolate-ga on 05 Apr 2006 21:24 PDT |
No one seems to have quite the correct answer. It is 1 minus the probability of both you and your brother losing. Losing is the same as the chance of picking 2 numbers less than or equal to 7 from a pile of numbers 1 thru 10. This is 7 choose 2 divided by 10 choose 2, that is, C(7,2)/C(10,2) which equals 7*6/(10*9). So the answer is 1 - 7*6/(10*9). |
Subject:
Re: Probability
From: rracecarr-ga on 05 Apr 2006 21:52 PDT |
uhhh.... That's the same answer as handlit's, ansel's, and mine. |
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