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Q: Probability ( No Answer,   8 Comments )
Question  
Subject: Probability
Category: Science > Math
Asked by: handlit33-ga
List Price: $2.00
Posted: 03 Apr 2006 15:33 PDT
Expires: 03 May 2006 15:33 PDT
Question ID: 715091
My brother and I are entered into a lottery of ten people total
(including ourselves).  Names will be pulled out of a hat, the 1st
name through 7th name are the losers.  The 8th name pulled is 3rd
place winning $20, the 9th name pulled is 2nd place winning $30 and
the 10th name pulled is 1st place winning $50.  What is the
probability that either my brother or me will win 1st, 2nd or 3rd
place?

I know that if the 1st, 2nd and 3rd names pulled were winners the
formula for figuring out the problem would be:

1 - 8/10*7/9*6/8

What is the probability and formula backing the answer for figuring
out the original way the question was stated?
Answer  
There is no answer at this time.

Comments  
Subject: Re: Probability
From: rracecarr-ga on 03 Apr 2006 16:36 PDT
 
I know the chance of heads is 1/2 the first time I flip a coin, but
what is it the last time?
Subject: Re: Probability
From: marcusl-ga on 03 Apr 2006 17:32 PDT
 
you have one draw, there are 10 options available, 3 winning options,
7 losing. 3/10 chance you win. also 3/10 your brother wins. combined,
you have a 6/10 chance of either of you winning. do your own homework!
Subject: Re: Probability
From: rracecarr-ga on 03 Apr 2006 17:44 PDT
 
Yes, do your own homework, but don't listen to marcus, or you'll get a bad grade.
Subject: Re: Probability
From: handlit33-ga on 03 Apr 2006 19:43 PDT
 
This isn't homework, haha.  I'm a 26 year old defense contractor,
school is a distant memory.  I'm just trying to educate myself on a
real world situation.
Subject: Re: Probability
From: rracecarr-ga on 04 Apr 2006 12:25 PDT
 
Ok, well the probability you list in your question is correct for any
three randomly drawn names.  First three, last three, any three. 
Essentially, the non-winning picks don't 'count'.  You don't even have
to look at them.
Subject: Re: Probability
From: ansel001-ga on 04 Apr 2006 17:29 PDT
 
The probability that either you or you brother or both will win one of
the three prizes is:

1 - [Probability you both lose]

As Rracecarr mentions, it doesn't matter where in the ten names drawn
the three winners lie, the probability is the same.  So your formula

1 - 8/10*7/9*6/8

is correct.
Subject: Re: Probability
From: berkeleychocolate-ga on 05 Apr 2006 21:24 PDT
 
No one seems to have quite the correct answer. It is 1 minus the
probability of both you and your brother losing. Losing is the same as
the chance of picking 2 numbers less than or equal to 7 from a pile of
numbers 1 thru 10. This is 7 choose 2 divided by 10 choose 2, that is,
C(7,2)/C(10,2) which equals 7*6/(10*9). So the answer is 1 -
7*6/(10*9).
Subject: Re: Probability
From: rracecarr-ga on 05 Apr 2006 21:52 PDT
 
uhhh....

That's the same answer as handlit's, ansel's, and mine.

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