Category: Reference, Education and News > Homework Help
Asked by: david0287-ga
List Price: $5.00
29 Apr 2006 09:52 PDT
Expires: 29 Apr 2006 12:03 PDT
Question ID: 723943
I have read a few websites and a book on trigonometric identities and I know that: cos x = sin 90 - x cos^2 + sin^2 x = 1 sin x / cos x = tan x I am not sure how to solve an equation whith z(sin x) and (cos y) For example sovle the equation: 3(sin 20) = cos(2x) [degrees] (find x for 0 <= x <=180) Thanks
|There is no answer at this time.|
From: kottekoe-ga on 29 Apr 2006 11:50 PDT
In general, equations like this cannot be solved without invoking the so-called inverse trigonometric functions. For example, to solve your example for x: z*sin(y) = cos(2x) We could write: 2x = arccos(z*sin(y)), where arccos(a) is the inverse of the cosine function Thus, we can formally solve it by saying: x = arccos(z*sin(y))/2 Unfortunately, your example has no solution, since 3*sin(20) is bigger than one and thus cannot equal cos(2x) for any value of x.
If you feel that you have found inappropriate content, please let us know by emailing us at firstname.lastname@example.org with the question ID listed above. Thank you.
|Search Google Answers for|