Google Answers Logo
View Question
 
Q: calculus question ( No Answer,   1 Comment )
Question  
Subject: calculus question
Category: Reference, Education and News > Homework Help
Asked by: cron1000-ga
List Price: $5.00
Posted: 01 May 2006 06:20 PDT
Expires: 03 May 2006 08:17 PDT
Question ID: 724366
Let f(x)= (ln x)/x for x>0. sketch the graph of y=f(x) indicating
asymptotes, regions where f is increasing, decreasing,convex, convave
,local extrema and points of inflection.  give absolute max and min
values on the interval {1,3}
Answer  
There is no answer at this time.

Comments  
Subject: Re: calculus question
From: ansel001-ga on 01 May 2006 18:30 PDT
 
Remember, you need to look at the first derivative to determine the
location of the maximum and/of minimum values.  These occur when the
first derivative is zero.  Also check values at the endpoints of the
interval.

Look at the second derivative to determine the points of inflection,
which occur when it is zero.  A negative second derivative indicates a
function that is concave downward and a positive second derivative
indicates a function that is concave upward.

To calculate a derivative of a quotient use the formula:

d/dx(u/v) = [v(du/dx) - u(dv/dx)] / v^2

f(x) = u/v = ln(x)/x

So  u = ln(x) and
    v = x

Here's a hint.  A well known constant may show up in the answer.

Important Disclaimer: Answers and comments provided on Google Answers are general information, and are not intended to substitute for informed professional medical, psychiatric, psychological, tax, legal, investment, accounting, or other professional advice. Google does not endorse, and expressly disclaims liability for any product, manufacturer, distributor, service or service provider mentioned or any opinion expressed in answers or comments. Please read carefully the Google Answers Terms of Service.

If you feel that you have found inappropriate content, please let us know by emailing us at answers-support@google.com with the question ID listed above. Thank you.
Search Google Answers for
Google Answers  


Google Home - Answers FAQ - Terms of Service - Privacy Policy