

Subject:
calculus question
Category: Reference, Education and News > Homework Help Asked by: cron1000ga List Price: $5.00 
Posted:
01 May 2006 06:20 PDT
Expires: 03 May 2006 08:17 PDT Question ID: 724366 
Let f(x)= (ln x)/x for x>0. sketch the graph of y=f(x) indicating asymptotes, regions where f is increasing, decreasing,convex, convave ,local extrema and points of inflection. give absolute max and min values on the interval {1,3} 

There is no answer at this time. 

Subject:
Re: calculus question
From: ansel001ga on 01 May 2006 18:30 PDT 
Remember, you need to look at the first derivative to determine the location of the maximum and/of minimum values. These occur when the first derivative is zero. Also check values at the endpoints of the interval. Look at the second derivative to determine the points of inflection, which occur when it is zero. A negative second derivative indicates a function that is concave downward and a positive second derivative indicates a function that is concave upward. To calculate a derivative of a quotient use the formula: d/dx(u/v) = [v(du/dx)  u(dv/dx)] / v^2 f(x) = u/v = ln(x)/x So u = ln(x) and v = x Here's a hint. A well known constant may show up in the answer. 
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