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 Subject: solving non-linear equation Category: Science > Math Asked by: emmag999-ga List Price: \$5.00 Posted: 08 May 2006 13:09 PDT Expires: 09 May 2006 14:09 PDT Question ID: 726654
 ```I need to solve (2ar^(a-1))-1 =0 Answer given in text is r = (2a)^(1/(1-a)), but I get to r = (2a)^(-1/(1-a))- where am I going wrong?```
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 Subject: Re: solving non-linear equation From: redfoxjumps-ga on 08 May 2006 13:21 PDT
 ```Is it "but I get to r = (2a)^(-1/(1-a))- where am I going wrong?" Or r = (2a)^(-1/(1-a)) ? if it is: r = (2a)^(-1/(1-a))- Do the two minus signs cancel each other out? or is one a typo?```
 Subject: Re: solving non-linear equation From: brix24-ga on 08 May 2006 17:06 PDT
 ```Do you get this for your second step 2ar^(a-1)=+1 ? Later, are you raising both sides to the (1/(a-1)) power? If these don't help, you might try posting your steps to make it easier for someone to pinpoint the problem.```
 Subject: Re: solving non-linear equation From: brix24-ga on 08 May 2006 17:08 PDT
 `Did you convert 1/2a to (2a)^-1?`
 Subject: Re: solving non-linear equation From: mathisfun-ga on 08 May 2006 23:16 PDT
 ```Are you getting r=(2a)^(-1/(1-a)) or r = (2a)^(-1/(a-1)) = (2a)^(1/(-(a-1)) = (2a)^(1/(-a+1) = (2a)^(1/(1-a)) If you are getting r = (2a)^(-1/1-a) then your problem is after you get r^(a-1) = 2a^-1 you are trying to take the (1-a)th root of each side instead of the (a-1)th leading to r^[(a-1)/(1-a)] = (2a)^(-1/(1-a)) which clearly doesn't solve for r. Hope this helps.```
 Subject: Re: solving non-linear equation From: redfoxjumps-ga on 09 May 2006 00:22 PDT
 ```Boy, ga picked a horrible default font for trying to communicate math problems! Instant headache font I think it is called.```