

Subject:
solving nonlinear equation
Category: Science > Math Asked by: emmag999ga List Price: $5.00 
Posted:
08 May 2006 13:09 PDT
Expires: 09 May 2006 14:09 PDT Question ID: 726654 
I need to solve (2ar^(a1))1 =0 Answer given in text is r = (2a)^(1/(1a)), but I get to r = (2a)^(1/(1a)) where am I going wrong? 

There is no answer at this time. 

Subject:
Re: solving nonlinear equation
From: redfoxjumpsga on 08 May 2006 13:21 PDT 
Is it "but I get to r = (2a)^(1/(1a)) where am I going wrong?" Or r = (2a)^(1/(1a)) ? if it is: r = (2a)^(1/(1a)) Do the two minus signs cancel each other out? or is one a typo? 
Subject:
Re: solving nonlinear equation
From: brix24ga on 08 May 2006 17:06 PDT 
Do you get this for your second step 2ar^(a1)=+1 ? Later, are you raising both sides to the (1/(a1)) power? If these don't help, you might try posting your steps to make it easier for someone to pinpoint the problem. 
Subject:
Re: solving nonlinear equation
From: brix24ga on 08 May 2006 17:08 PDT 
Did you convert 1/2a to (2a)^1? 
Subject:
Re: solving nonlinear equation
From: mathisfunga on 08 May 2006 23:16 PDT 
Are you getting r=(2a)^(1/(1a)) or r = (2a)^(1/(a1)) = (2a)^(1/((a1)) = (2a)^(1/(a+1) = (2a)^(1/(1a)) If you are getting r = (2a)^(1/1a) then your problem is after you get r^(a1) = 2a^1 you are trying to take the (1a)th root of each side instead of the (a1)th leading to r^[(a1)/(1a)] = (2a)^(1/(1a)) which clearly doesn't solve for r. Hope this helps. 
Subject:
Re: solving nonlinear equation
From: redfoxjumpsga on 09 May 2006 00:22 PDT 
Boy, ga picked a horrible default font for trying to communicate math problems! Instant headache font I think it is called. 
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