Very first, Chow test is a application of F test.
If you know how to interpret F test, you should be able to interpret Chow test.
F test hypothesis looks like
H_0 : X1=0,X2=1,X3=3
H_1 : H_0 is false
So F statistics tests... how untruthful is the null hypothesis. It is
one tailed test. (If I remember correctly, I never got confused of
one-tail test or two-tail test to operate. The F-table only refers two
degrees of freedom - SAS apparently gives Num DF and DEN DF.)
It is really difficult to see because the output you pasted was
wrapped. But SAS gave you this result:
Test Point Num DF Den DF F Value Pr > F
Chow 20 3 33 3.39 0.0295
It says: "Test was selected to be 'Chow Test'. (I don't know what
Break Point refers) Numerator Degrees of Freedom is 3. Denominator
Degrees of Freedom is 33. F Value of the test was 3.39. Thus the
probability, Pr(F>3.39)~0.0295." So, depending on your significance
level, you will find the test reject or fail to reject the null
In the beginning, there is some descriptive statistics about errors,
thus goodness of fit. The last thing I suppose is the testing of
significance of each variable you tested in Chow Test...