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 Subject: Integration Category: Science > Math Asked by: real_madras-ga List Price: \$5.00 Posted: 30 May 2006 10:28 PDT Expires: 29 Jun 2006 10:28 PDT Question ID: 733691
 `How do you integrate log(z - e^(ix))?`
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 ```I x Integrate[Log[z - E ], x] = -I 2 I x -- x + x Log[-E + z] - 2 I x E 2 I x Log[1 - ----] -x z I z (--- - ----------------- - 2 z z I x E PolyLog[2, ----] z ----------------) z Answer provided by: http://integrals.wolfram.com/ Go there, enter "Log[z-E^(I*x)]" and click "Compute" to see the result in a better (non-ASCII) format. Regards, df```
 ```using the taylor series you get e^ix = cosx +isinx, this may make is easier to integrate. Also trying using intergrator.com. I swear by it. Hope this helps. Preston```
 ```Would you please clarify this question? You could mean log(z - exp( i Re(z))), but then you would have to describe the contour. Or you could simply have made a mistake using z and x and want the indefinite integral of log( x - exp (ix)). Or ... ?```