

Subject:
Integration
Category: Science > Math Asked by: real_madrasga List Price: $5.00 
Posted:
30 May 2006 10:28 PDT
Expires: 29 Jun 2006 10:28 PDT Question ID: 733691 
How do you integrate log(z  e^(ix))? 

There is no answer at this time. 

Subject:
Re: Integration
From: dgfinckga on 02 Jun 2006 20:59 PDT 
I x Integrate[Log[z  E ], x] = I 2 I x  x + x Log[E + z]  2 I x E 2 I x Log[1  ] x z I z (    2 z z I x E PolyLog[2, ] z ) z Answer provided by: http://integrals.wolfram.com/ Go there, enter "Log[zE^(I*x)]" and click "Compute" to see the result in a better (nonASCII) format. Regards, df 
Subject:
Re: Integration
From: postlp60ga on 04 Jun 2006 17:46 PDT 
using the taylor series you get e^ix = cosx +isinx, this may make is easier to integrate. Also trying using intergrator.com. I swear by it. Hope this helps. Preston 
Subject:
Re: Integration
From: berkeleychocolatega on 06 Jun 2006 11:18 PDT 
Would you please clarify this question? You could mean log(z  exp( i Re(z))), but then you would have to describe the contour. Or you could simply have made a mistake using z and x and want the indefinite integral of log( x  exp (ix)). Or ... ? 
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