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Q: Integration ( No Answer,   3 Comments )
Subject: Integration
Category: Science > Math
Asked by: real_madras-ga
List Price: $5.00
Posted: 30 May 2006 10:28 PDT
Expires: 29 Jun 2006 10:28 PDT
Question ID: 733691
How do you integrate log(z - e^(ix))?
There is no answer at this time.

Subject: Re: Integration
From: dgfinck-ga on 02 Jun 2006 20:59 PDT
I x
Integrate[Log[z - E   ], x] =

-I  2           I x
-- x  + x Log[-E    + z] - 
                          I x
         2   I x Log[1 - ----]
       -x                 z
  I z (--- - ----------------- - 
       2 z           z
                 I x
     PolyLog[2, ----]

Answer provided by:
Go there, enter "Log[z-E^(I*x)]" and click "Compute" to see the result
in a better (non-ASCII) format.

Subject: Re: Integration
From: postlp60-ga on 04 Jun 2006 17:46 PDT
using the taylor series you get e^ix = cosx +isinx, this may make is
easier to integrate.

Also trying using I swear by it.
Hope this helps.

Subject: Re: Integration
From: berkeleychocolate-ga on 06 Jun 2006 11:18 PDT
Would you please clarify this question? You could mean log(z - exp( i
Re(z))), but then you would have to describe the contour. Or you could
simply have made a mistake using z and x and want the indefinite
integral of log( x - exp (ix)). Or ... ?

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