Find f(2),f(3),f(4),and f(5) if f is defined recursively by
f(0)=f(1)=1 and for n=1,2.....
a.)f(n+1)=f(n)-f(n-1)
b.)f(n+1)=f(n) f(n-1)
c.)f(n+1)=f(n)^2 + f(n-1)^3
d.)f(n+1)=f(n)/f(n-1)

Must show your work please!

a) f(2) = f(1) - f(0) = 1 -1 = 0
   f(3) = f(2) - f(1) = 0 - 1 = -1

You should be able to do the rest of your homework yourself.