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 Subject: Gas and Volume Category: Science > Physics Asked by: alwysnforevr002-ga List Price: \$2.00 Posted: 22 Jul 2006 17:51 PDT Expires: 21 Aug 2006 17:51 PDT Question ID: 748636
 ```A container of gas is at a pressure of 3.7 X 10(to the fifth) Pa. How much work is done by the gas if its volume expands by 1.6 m3? This is the equation i thought fit best for this question: Work done by the net force = final kinetic energy - starting kinetic energy```
 ```You need more information about the type of expansion. Is it adiabatic? Isothermal? Or is the pressure somehow kept constant during the expansion?```
 ```Also... is the gas ideal? I'm guessing it's probably an ideal gas under going isobaric expansion in which case, W = integral (pressure* dVolume) = pressure * integral (dVolume) = pressure * DeltaVolume (deltaVolume is the change in volume) If it's not isobaric and the gas is ideal, Then PV = nRT (ideal gas law) => P = nRT/V W = integral (nRT/V * dVolume) If you assume the expansion is isothermal, then temperature has no dependence on volume, pressure by definition: W = nRT * integral (dV/V) = nRT * ln (Vol_f/Vol_i) n = number of moles of the gas R = 'universal' gas constant 8.3145 J/(Mol*K) Hope that helps..```