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Subject:
probability
Category: Science > Math Asked by: tlcmkt-ga List Price: $40.00 |
Posted:
29 Jul 2006 14:20 PDT
Expires: 02 Aug 2006 05:00 PDT Question ID: 750699 |
There are x number of phone lines connected to an 800 number, which can take x calls simultaneously. On average, it takes y seconds to answer one call. When there are more than x people calling, additional callers will be put on hold, until someone gets off and a phone line is available to answer the call. Let z be the average number of people calling in an hour. Assume everyone calls on the second. Formulate the probability for the wait-time (t), in terms of x, y, and z. (The wait-time is the number of seconds caller be put on hold before the call is answered. ) |
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There is no answer at this time. |
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Subject:
Re: probability
From: berkeleychocolate-ga on 29 Jul 2006 22:12 PDT |
There is not enough information to answer the question. One needs the distribution of calls in and the distribution of time to answer a call. Typically the distribution of calls in is Poisson and the answer times are exponential. If these assumptions are made, then the question can be answered. |
Subject:
Re: probability
From: tlcmkt-ga on 30 Jul 2006 05:17 PDT |
Thank you for your comments. This is an automatic phone service system. Duration for each call is constant, y. Assume there are z incoming calls every hour, and they have equal chance of calling on any second during that hour. Thanks again. |
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