Given a 2D oval with origin x,y and x radius of xr and y radius of yr
what is the equation to plot the individual points of the permiter?

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Clarification of Question by michaelo1966-ga on 16 Aug 2006 18:33 PDT

Whoops -- forgot something -- want to know the point also given an
angle.  So if original is x, y and x radius is xr and y radius is yr
and angle is a (0-360) what is the x/y location of the permiter?

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Clarification of Question by michaelo1966-ga on 17 Aug 2006 07:43 PDT

OK -- I answered my own question but thought I'd post here.  Maybe I
get my own $2?  Or if I stumble into a time machine I'll be that much
more likely to pass geometry.

Answer:

/*
 * Oval is object with properties:
 *   x = x center
 *   y = y center
 *   xr = x radius
 *   yr = y radius
 */
function getOvalPoint(oval:Object, angle:Number, offset:Number):Point
{
  if(offset==undefined){ offset = 0; }
	
  var radians:Number = degreesToRadians(angle);	
  var px:Number = oval['x'] + Math.cos(radians) * (oval['rx']+offset);
  var py:Number = oval['y'] + Math.sin(radians) * (oval['ry']+offset);	
	
  return new Point(px, py);
}