

Subject:
Help with a math problem
Category: Reference, Education and News > Homework Help Asked by: maxmousega List Price: $5.00 
Posted:
24 Aug 2006 11:11 PDT
Expires: 24 Aug 2006 14:11 PDT Question ID: 759137 
I got a math problem that looks like this. Find the point P in the first quadrant on the curve y=x^3 such that the slope of the line passing through P and (1,1) is 3. I used substitution and the definition of slope to solve it. My answer is (2,8) and the computer says it's incorrect. Anyone know the correct answer and how to get there, so I can find my mistake. 

There is no answer at this time. 

Subject:
Re: Help with a math problem
From: bcattwoodga on 24 Aug 2006 12:32 PDT 
(2,8) is not in the first quadrant (x>0, y>0). This appears to be a poorly conceived trick question or something because (hint approaching) the only P that kind of works doesn't even form a line with (1,1). 
Subject:
Re: Help with a math problem
From: philnjga on 24 Aug 2006 13:42 PDT 
Yep. Trick question or bad question. The polynomial and the line at (1,1) only intersect at two points, first and third quadant. Maxmouse found the third quadrant point (that should count for something). The first quadrant point is (1,1), not a valid choice when defining a line. Funny, the polynomial for the intersection has three roots, but two of them are the same. This was a fun problem to solve at the end of a hard day. Brushed up on some algebra I had forgotten. 
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