Can anyone solve the integral below, ie, get a closed form solution?

Let N(x) denote the normal cumulative distribution, n(x)=N' the normal
density function (n(x)=1/Sqrt(2 pi)*exp(-.5 x^2)), then this integral
can be solved:

Integral {N(x) n(x)} dx  =  1/2*N(x)^2

Does anybody knwo how the following, very similar integral can be
solved in closed form:

Integral {N(x) n(x+c)} dx  =  ?   [c is a constant]

Thanks,
Martin