

Subject:
Volume of Revolution Problem
Category: Science > Math Asked by: jeremitga List Price: $25.00 
Posted:
25 Sep 2006 15:18 PDT
Expires: 26 Sep 2006 09:20 PDT Question ID: 768353 
The region is bounded by the curves y=cosx, y=e^3\2x, x=o and is revolved about the xaxis. The first point at which the curves intersect in the first quadrant is revolved about the xaxis. Here is the graph setup that I derived from the given information: http://img137.imageshack.us/my.php?image=washergraphjk7.jpg I can see that this has to be solved using the washer method due to the hole that would result in the center.....so the equation for the washer method is: http://img137.imageshack.us/my.php?image=washereqnap7.jpg and the values for the definite integral are found by taking the x values where the two graphs intersect. I was wondering if I this was the correct setup to solve the equation: http://img105.imageshack.us/my.php?image=washersetupue9.jpg I wasn't really sure if I setup this right because it seems like the definite integral was more complicated than it needed to be and ran into some trouble while trying to solve it. 

There is no answer at this time. 

Subject:
Re: Volume of Revolution Problem
From: barnecaga on 26 Sep 2006 02:16 PDT 
your setup looks correct to me. recheck your integration; the integral you have is not that hard to do. break into two terms; integral of pi*cos^2(x)dx, and integral of pi*e^(3x)dx. each integral is fairly easy to do. cab 
Subject:
Re: Volume of Revolution Problem
From: jeremitga on 26 Sep 2006 09:05 PDT 
ohhhhhhhhhhh ok. I don't know why it didn't cross my mind to break up the integrals. Im the one who made it harder than it needed to be. 
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