

Subject:
Simple Maths Problem?
Category: Science > Math Asked by: jubsterga List Price: $2.00 
Posted:
06 Oct 2006 05:34 PDT
Expires: 05 Nov 2006 04:34 PST Question ID: 771259 
How can I get the numbers 2, 3, 7 and 8 to equal 22 using just normal +, , x and / maths functions (and brackets)? All the numbers have to be used, but they only can be used once. 

There is no answer at this time. 

Subject:
Re: Simple Maths Problem?
From: toufarooga on 06 Oct 2006 11:29 PDT 
one way i thought up was "27"  8 + 3 other than that, i can't really think of a way...i can get 19,20,21,23,24... 
Subject:
Re: Simple Maths Problem?
From: theduffmanga on 07 Oct 2006 00:21 PDT 
also 23 + 7  8 but I don't think that qualifies. No, I'm stumped too 
Subject:
Re: Simple Maths Problem?
From: pafalafaga on 07 Oct 2006 05:54 PDT 
decimals...? 7 x 3 + .2 + .8 = 22 
Subject:
Re: Simple Maths Problem?
From: emollga on 08 Oct 2006 18:09 PDT 
Well, it's just 2+3+7+8 if you do it in Base 9. . . . 
Subject:
Re: Simple Maths Problem?
From: jcuestaga on 13 Oct 2006 23:19 PDT 
Define A,B,C,D as integer variables; then combine it with the numbers 2,3,7,8 and obtain a set of integer equation problems: 2A + 3B + 7C + 8D  22 = 0 subject to: A,B,C,D in Z Solutions: (2,1,1,1), (3,3,1,0),... obtained with Excel Solver Other possibilities: products (2*3), ...(7*8) quocients (2/3), ... (7/8) Example: (2*3)A + 7B + 8C  22 = 0 subject to: A,B,C in Z Solutions: no solution in this case 
Subject:
Re: Simple Maths Problem?
From: aaronksuga on 15 Oct 2006 12:35 PDT 
well, if you follow the rules of math operations, (P,E,M,D,A,S) 2 + 3 * 8  4 = 22 3*8 = 24 2+244 = 22 
Subject:
Re: Simple Maths Problem?
From: aaronksuga on 15 Oct 2006 12:36 PDT 
eeehhg.... nvm..I used wrong numbers 
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