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| Subject:
Chemistry - Solubility Products Ksp
Category: Science > Chemistry Asked by: medicine_man-ga List Price: $2.50 |
Posted:
10 Oct 2006 18:22 PDT
Expires: 10 Oct 2006 23:36 PDT Question ID: 772493 |
The solubility of magnesium carbonate, MgCO3, in aqueous solution at 25oC is 4.5 x 10^-3 mol L-1. The solubility product, Ksp, of MgCO3 at 25oC is? Please show workings on how you acheived the answer. Cheers :) |
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| Subject:
Re: Chemistry - Solubility Products Ksp
From: dr_morph-ga on 10 Oct 2006 19:40 PDT |
Magnesium carbonate MgCO3 6.82×10-6 http://www.ktf-split.hr/periodni/en/abc/kpt.html |
| Subject:
Re: Chemistry - Solubility Products Ksp
From: dr_morph-ga on 10 Oct 2006 19:52 PDT |
p.s. I think that since the Ksp is 6.82*10^-6, therefore the solubility is the square root of 6.82*10-6, since Ksp=[Mg][CO3]. Therefore the solubility is not 4.5 x 10^-3, but is actually 2.6 x 10^-3 |
| Subject:
Re: Chemistry - Solubility Products Ksp
From: dr_morph-ga on 10 Oct 2006 19:56 PDT |
however, assuming you are correct, and paying for this ;), if the solubility is 4.5 x 10^-3, therefore [mg]=4.5 x 10^-3 and [CO3]=4.5 x 10^-3, and Ksp=[Mg][CO3]Ksp=(4.5 x 10^-3)^2 = 2.025 X 10^-5 |
| Subject:
Re: Chemistry - Solubility Products Ksp
From: medicine_man-ga on 10 Oct 2006 23:34 PDT |
The second answer is correct thanks for your time and effort :) |
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