Category: Science > Chemistry
Asked by: chemstudent3625-ga
List Price: $2.00
27 Oct 2006 09:58 PDT
Expires: 26 Nov 2006 08:58 PST
Question ID: 777489
Using the following balanced equation: Ammonia is produced by the reaction of hydrogen and nitrogen N2(g) + 3 H2(g) yields 2 NH3(g) How many moles of N2 reacted if 0.66 mole of NH3 is produced? How many moles of NH3 are produced when 2.7 moles of H2 reacts?
Answered By: livioflores-ga on 28 Oct 2006 07:14 PDT
Hi!! The balanced equation gives us the ratio between moles of products of reaction and moles of reactives; in this case it tells us that for each 2 moles of NH3 produced we need 1 mol of N2, so the ratio between them for this reaction is 1/2, then for 0.66 moles of NH3 we will need: 0.66 * 1/2 = 0.33 moles of N2. In the same way when 3 moles of H2 react we obtain 2 moles of NH3, so the ratio between them for this reaction is 2/3, then when 2.7 moles of H2 react we will obtain: 2.7 * 2/3 = 1.8 moles of NH3 For references see: "Chemical Reactions": http://chemed.chem.purdue.edu/genchem/topicreview/bp/ch3/equations.html "Stoichiometry Problems": http://members.aol.com/profchm/stoic.html I hope this helps you. Feel free to request for a clarification if you need it. Regards, livioflores-ga
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