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Q: Computing DCT coefficients using DFT. ( No Answer,   0 Comments )
Subject: Computing DCT coefficients using DFT.
Category: Reference, Education and News > Homework Help
Asked by: budday-ga
List Price: $10.00
Posted: 24 Nov 2006 15:27 PST
Expires: 24 Dec 2006 15:27 PST
Question ID: 785334
For signal u[n],n=0,1,....N-1, show that its DCT coefficients w[k],k=0,1,...N-1
can be computed as follows:
w[k]=sqrt[2(2-del[k])]R{e to the power-j(pi)k/2N v'[k]}where del[k] is
the Kronecker Delta, R denotes the real part of a complex number and
v'[k]is the Unitary DFT coefficient for signal u'[n] belongs to R to
the power 2N defined as follows:
Transpose of(u')=[u[0]u[1].....u[N-1]00...0],i.e u'is the zero padded
version(upto length 2N)of u.

Based on the above derivation, describe steps needed to implement fast
DCT using FFT.
There is no answer at this time.

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