Google Answers Logo
View Question
 
Q: Projective Geometry Problem ( No Answer,   3 Comments )
Question  
Subject: Projective Geometry Problem
Category: Science > Math
Asked by: cyberdima-ga
List Price: $50.00
Posted: 29 Nov 2006 08:09 PST
Expires: 29 Dec 2006 08:09 PST
Question ID: 786570
Construction: Suppose that P is projective plane that satisfies
Desaragues axiom. Let L be an arbitrary line of P and p be an
arbitrary point on L. Define D = L - {p}.
Question: Proof that possible to define on D two operations (D,+,?),
so D will be division ring and each element is reversible.
Answer  
There is no answer at this time.

Comments  
Subject: Re: Projective Geometry Problem
From: d10s-ga on 29 Nov 2006 19:32 PST
 
What does "reversible" means ?
Subject: Re: Projective Geometry Problem
From: mathtalk-ga on 07 Dec 2006 15:05 PST
 
In the context (division ring), I feel sure cyberdima-ga means "invertible".

regards, mathtalk-ga
Subject: Re: Projective Geometry Problem
From: mathtalk-ga on 29 Dec 2006 19:54 PST
 
A basic introduction to the construction of "ternary rings" from
projective planes is found in this column:

[This Week's Finds in Mathematical Physics (Feb. 9, 2000) -- John Baez]
http://math.ucr.edu/home/baez/week145.html

A quick summary:  Projective planes are incidence structures, where
points and lines play dual roles.  E.g. two points determine a line
incident with both points, and two lines determine a point where both
lines intersect.

The column linked above also defines a Desarguesian projective plane
and describes (without proof) the equivalence of this geometric
property to the "ternary ring" constructed from the projective plane
being a division ring.

A proof of Desargues' Theorem for the real projective plane, using
vector algebra, is given in the Wikipedia article:

[Desargues' theorem -- Wikipedia]
http://en.wikipedia.org/wiki/Desargues%27_theorem

which also provides a link to an alternative proof (also using vector
algebra) at PlanetMath:

[Proof of Desargues' theorem  -- PlanetMath]
http://planetmath.org/?op=getobj&from=objects&id=4514

A proof that a projective plane constructed from a division ring is
Desarguesian can be similar to the above calculations in use of vector
algebra.  Proof of the converse is more challenging.  There is a proof
given (in PostScript format) here in Section 6.4 based on some
"machinery" of perspectivities in projective planes and a concept of a
Desarguesian projective lines:

[6. Projective and affine spaces]
www.win.tue.nl/~amc/buek/B06.ps


regards, mathtalk-ga

Important Disclaimer: Answers and comments provided on Google Answers are general information, and are not intended to substitute for informed professional medical, psychiatric, psychological, tax, legal, investment, accounting, or other professional advice. Google does not endorse, and expressly disclaims liability for any product, manufacturer, distributor, service or service provider mentioned or any opinion expressed in answers or comments. Please read carefully the Google Answers Terms of Service.

If you feel that you have found inappropriate content, please let us know by emailing us at answers-support@google.com with the question ID listed above. Thank you.
Search Google Answers for
Google Answers  


Google Home - Answers FAQ - Terms of Service - Privacy Policy