Google Answers Logo
View Question
Q: Supernova light curve and Cobalt 56 decay ( No Answer,   0 Comments )
Subject: Supernova light curve and Cobalt 56 decay
Category: Science > Physics
Asked by: skot85-ga
List Price: $20.00
Posted: 29 Nov 2006 09:31 PST
Expires: 29 Dec 2006 09:31 PST
Question ID: 786607
I have plotted a light curve from a supernova (SN2004DJ) in several
different bands (V, B and R) and have achieved what amounts to a
straight line on a plot of magnitude against time.  This is to be
expected as magnitude is a log scale and the light curve decays
exponentially.  I also want to include on this graph a line showing
the decay rate of Cobalt 56 which is thought to cause supernovae
remnants to radiate long efter they would have otherwise disapeared. 
Whenever I do a calculation to work out the gradient of the Cobalt
line, it comes out to be around 260 days per magnitude.  This is
totally different from the value quoted in a research paper about the
same supernova.  A copy of this paper can be found at:  This gives it as around
1 magnitude every 100 days.

Can anybody help me to do this calculation?  The half-life of Cobalt
56 is 77.27 days if that helps.

I know this is a very specialised question and might well go in the
Mathematics section as well.  If you happen to be an expert in this
area, please help!  Thank you.
There is no answer at this time.

There are no comments at this time.

Important Disclaimer: Answers and comments provided on Google Answers are general information, and are not intended to substitute for informed professional medical, psychiatric, psychological, tax, legal, investment, accounting, or other professional advice. Google does not endorse, and expressly disclaims liability for any product, manufacturer, distributor, service or service provider mentioned or any opinion expressed in answers or comments. Please read carefully the Google Answers Terms of Service.

If you feel that you have found inappropriate content, please let us know by emailing us at with the question ID listed above. Thank you.
Search Google Answers for
Google Answers  

Google Home - Answers FAQ - Terms of Service - Privacy Policy