

Subject:
Engineeringing Physics
Category: Science > Physics Asked by: pj4444ga List Price: $4.00 
Posted:
01 Apr 2003 21:46 PST
Expires: 05 Apr 2003 19:53 PST Question ID: 184693 
A man pushes a 16 kg lawn mower at a constant speed with a force F = 90 N directed along the handle, which is at an angle of 45° to the horizontal (see below). Calculate: a.the horizontal retarding force on the mower; b.the normal force exerted vertically upward on the mower by the ground; and c.the force the man must exert on the lawn mower to accelerate it from rest to 1.5 ms1 in 2.5 seconds. Assume the same retarding force. 

There is no answer at this time. 

Subject:
Re: Engineeringing Physics
From: racecarga on 02 Apr 2003 14:16 PST 
a) retarding force is the same as the horizontal force exerted by the man, that is 90/sqrt(2) N. 64 N b) the weight of the mower (16kg * 9.8 N/kg) plus the vertical force exerted by the man, which is 90/sqrt(2) N. 220 N c) net force is mass*acceleration. acceleration = 1.5/2.5 m/s^2 = .6 m/s^2, so net force is .6 m/s^2 * 16 kg = 9.6 N. In addition there is 90/sqrt(2) N retarding force. 73 N 
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