How many grams of NaHCO3 (battery acid) would you need to neutralize
500ml of battery acid (H2S04) that has been spilled on your garrage
floor?
Assume that the concentration of the battery acid is 12molL-1
The balance equation is:
H2SO4 + 2NaHCO3-----Na2SO4 +2CO2+ 2H20

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Clarification of Question by teriberry-ga on 13 Nov 2006 14:25 PST

How many grams of NaHCO3 (baking soda) would yuo need to neutralise
500ml 0f of battery acid (H2SO4) that has been spilled on your garage
floor ?
Assume that the concentration of the battery acid is 12molL-1 
The balance equation is:
H2SO4 + 2NaHCO3-----Na2SO4 + 2CO3 + 2H2O

You need to do the following 3 steps:

1. From the volume and concentration, figure out how many moles of H2SO4 there are.

2. From the balanced equation, you know that you need twice as many
moles of NaHCO3 to complete the reaction.

3. From the number of moles of NaHCO3 you got in (2), and also from
it's molecular weight in grams-per-mole, figure out how many grams are
needed.